Correct Answer - C
Strength of the solution = 34 g/L
1 L of the solution contains 34 g of `H_(2)O_(2)`
200 mL of the solution contains `(34)/(1000)xx200=6.8 g` of `H_(2)O_(2)`
`underset(2xx34 g)(2H_(2)O_(2))to 2H_(2)O+underset(32 g)(O_(2))`
68 g of `H_(2)O_(2)` gives 32 g of `O_(2)`
6.8 g of `H_(2)O_(2)` gives `= (32)/(68)xx6.8=3.2g` of `O_(2)`