Question

What will be the energy of each photon in monochromatic light of frequency 5 × 10¹⁴ Hz?

Answer 1

Data: y = 5 × 10¹⁴ Hz, h = 6.63 × 10^-34 Js,

1eV =1.6 × 10^-19 J

The energy of each photon,

E = hv = (6.63 × 10^-34 J.s)(5 × 10¹⁴ Hz)

= 3.315 × 10^-19 J

= \(\cfrac{3.315\times10^{-19}J}{1.6\times10^{-19}{\frac{j}{eV}}}\) = 2.072 eV