In the first case, as the expansion is against constant external pressure
`W = p_("ext") (V_(2) - V_(1)) = - 2 "bar" xx (50 - 10) L`
`= - 80 L "bar" " " (1 L "bar" = 100 J)`
`= - 80 xx 100 J`
`= - 8 kJ`
If the given expansion was carried out reversibly, the internal pressure of the gas should be greater than the external pressure at every stage. Hence, the work done will be more