Question

For the reaction
`2CO +O_(2) rarr 2CO_(2), DeltaH =- 560 kJ`,
`2mol` of `CO` and `1mol` of `O_(2)` are taken in a container of volume `1L`. They completely form `2 mol` of `CO_(2)`. The gaseous deviate appreciably from ideal behaviour. If the pressure in the vessel changes from `70` to `40atm`, find the magnetic (absolute) value of `DeltaU at 500K. (1 L-atm = 0.1 kJ)`

Answer 1

`DeltaH = DeltaU +Delta(PV)`
`DeltaU = DeltaH - Delta(PV)`
`=- 560 - V(P_(2)-V_(1))`
`=- 560 -1(40 - 70) xx 0.1`
`=- 557 kJ`