Question

`16g` oxygen gas expands at `STP` to occupy double of its oxygen volume. The work done during the process is:
A. `260 kcal`
B. `180 kcal`
C. `130 kcal`
D. `272.84` kcal

Answer 1

Correct Answer - D
At `STP 16 g O_(2)` or `1/2` mole `O_(2)` will occupy `11.2` litre. Thus if volume is doubled, it means `(V_(2)-V_(1))=22.4-11.2=11.2 litre`
`W=Pxx(V_(2)-V_(1))=1xx11.2 litre -atm`
`=(1xx11.2xx2)/0.0821 cal =272.84 kcal`