Question

A gas expands from `3 dm^(3)` to `5dm^(3)` anainst a constant pressure of `3atm`. The work done during the expansion if used ti heat `10mol` of water at temperature `290K`. Find the final temperature of water, if the specific heat of water `= 4.18g^(-1)K^(-1)`.

Answer 1

Work done `P DeltaV = (3 xx2) L-atm`
`DeltaV = 5- 3 = 2=3xx2xx101.3J = 607.8J`
Heat lost `=` Heat gained by `H_(2)O (ms Deltat)`
`Deltat = (607.8)/(10xx18xx4xx4.18) = 0.808K`
`rArr T_(f) = 290 +0.808 = 290.808K`