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The oxide `TI_(n) , Ca_(2), Ba_(2) Cu_(u) O_(14)` is found to be superconductor at 125 K. the value of n is

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Correct Answer - 6
As given molecule is neutral, sum of oxidation state = 0 . Hence
n (+3) + 2 ( +2) + 2 ( +2) + 3 ( +2) + 10 ( -2) =0
or 3 n + 4 + 4 + 6 -20 = 0 or 3 n = 6 or n =2

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