Data: Vo = 0.8 V, λ = 4950 Å = 4.950 × 10-7 m,
Vo ‘ = 1.2V, h = 6.63 × 10-34 J∙s, c = 3 × 108 m/s.
(i) Voe = hv – Φ = \(\cfrac{hc}{\lambda}\) – Φ
∴ The work function of the cathode material,
(ii) Vo'e = \(\cfrac{hc}{\lambda'}\) - Φ
∴ \(\cfrac{hc}{\lambda'}\) = Vo'e + Φ
∴ The wavelength of the second sources,
\(\lambda'\) = \(\cfrac{hc}{V_o{'}e+\phi}\)