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The number of isomers of dibromederivative of an alkene (molar mass 186 g `mol^(-1)`) is
A. 2
B. 3
C. 4
D. 6

1 Answer

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Correct Answer - B
2-C+2H+2Br=186
`Br_(2)-C=CH_(2)` and `underset("2-Geometrical isomer")(Br-CH=CH-Br)`
We know that alkene have minimum one double bond. If we take 2-Bromine atoms it will have 160 mol. Weight so remaining will be 2C and 2-H there 2-Br atoms placed at one carbon or both carbon can have one Br respectively. which will give geometrical isomerism (2-Forms).

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