Question

0.14 gm of an acid required 12.5 ml of 0.1 N `NaOH` for complete neuturalisation.The equivalent mass of the acid is:
A. 63
B. 56
C. 45
D. 112

Answer 1

Correct Answer - D
mEq. Of `NaOH=12.5xx0.1`
`=1.25`
mEq. Of acid `=mEq. Of NaOH`
Equivalent `=(Wt.)/(Ew)`
`Ew=(Wt.)/("Equivalent "(0.14)/(1.25xx10^-3)`
`=112`