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The `K_(b)` of weak base is `10^(-4)`. The `["salt"]` to `["base"]` ratio to be maintained to keep the `P^(H)` of buffer solution as `9` is .
A. `1 : 4`
B. `4 : 2`
C. `1 : 10`
D. `10 : 1`

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Correct Answer - D
`P^(H) = 14 - P_(kb) - "log" (["Salt"])/(["Base"])`
`([S])/([B]) = 10 : 1`

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