Question

Calculate the percentage of `BaO` in `29.0 g` mixture of `BaO` and `CaO` which just reacts with `100.8 mL` of `6.0M HCl`.

Answer 1

Let a g of `BaO` and b g of `CaO` are present.
`:. a+b=29`….(i)
Meq. of `BaO+Meq`. of `CaO=Meq`.of `HCl`
`:. 56a+153b=2591`….(iii)
By eq. (i) and (ii), `a=19.03 g, b=9.97 g`
`:. %` of `BaO=(19.03)/(29)xx100= 65.62%`

Comments

How 2591 value for HCL