`D.U.` IN `C_(6)H_(10)=((2n_(C)+2)-n_(H))/(2)=(14-10)/(2)=2^(0)`
`(` Two `(C=C)` bonds `).` Both the double bonds should be terminal so that it does not show geometrical isomers.
`I.`
Hexa `-1,5-`diene
`II.`
`3-`Methyl prenta `-1,4-`diene
`III.`
`2-`Methyl penta `-1,4-`diene
`IV.`
`2,3-`Dimethyl buta `-1,3-`diene
`V.`
`2-`Ethyl buta `-1,3-`diene
If bond is internal, it must contain two same groups, so that it does not show geometrical isomers.
`VI.`
`4-`Methyl penta `-1,3-` diene
Total number of isomers `=6`
