Question

The radius of a water molecule having density `1.0g mL^(-1)` is :
A. `1.925 Å`
B. `73.46Å`
C. `19.25Å`
D. `7.346Å`

Answer 1

Correct Answer - A
`V=4//3 pir^(3)`
Also volume of `1 "molecule"`
`=(18)/(6.023xx10^(23))mL ( :. 1 g=1 mL)`
`:. r^(3)=(3xx18)/(6.023xx10^(23)xx4xx3.14)`
`r=1.925xx10^(-8)cm`