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`100 mL` of mixture of `NaOH` and `Na_(2)SO_(4)` is neutralised by `10 mL` of `0.5 M H_(2) SO_(4)`. Hence, NaOH in `100 mL` solution is
A. `0.2 g`
B. `0.4 g`
C. `0.6 g`
D. none of these

1 Answer

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Best answer
Correct Answer - B
`Meq. of NaOH=10xx0.5xx2=10`
`:. (w)/(98//3)xx1000=10`
`:. w=0.4 g`

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