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How many moles of electrons weigh one kilogram?
A. `6.023xx10^(23)`
B. `(1)/(9.108)xx10^(23)`
C. `(6.023xx10^(54))/(9.108)`
D. `(1)/(9.108xx6.023)xx10^(8)`

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Correct Answer - D
`9.108xx10^(-31)kg=1`electron
therefore `1 kg =(1)/(9.108xx10^(-31))`electron
`=(1)/(9.108xx10^(-31))xx(1)/(6.023xx10^(23))`mole electron
`=(10^(8))/(9.108xx6.023)`

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