Question

A `6.90 M` solution of `KOH` contains 30% by weight of `KOH`. Calculate the density of the solution.
A. `1.288g//mL`
B. `12.88 g //mL`
C. `0.1288g//mL`
D. None of these

Answer 1

Correct Answer - A
Molarity of `KOH=(30)/(56xx(100)/(d))xx1000`
`therefore 6.90=(30xx10xxd)/(56)`
`therefore d=1.288g//mL`