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Sulphur trioxide may be prepared by the following two reactions:
`S_(8)+8O_(2(g))rarr 8SO_(2(g))`
`2SO_(2(g))+O_(2(g))rarr 2SO_(3(g))`
How many grams of `SO_(3)` will be produced from `1` mole of `S_(8)`?

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`S_(8)rarr8SO_(2)rarr8SO_(3)`
`1 "mole"S_(8)-=8"mole"SO_(3)`
or `32xx8gS=8xx80g SO_(3)`
`= 640 g`

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