Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
62 views
in Chemistry by (67.3k points)
closed by
A sodium salt of unknown anion when treated with `MgCl_(2)` gives a white `ppt`. On boiling. The anion is
A. `HCO_(3)^(Θ)`
B. `CO_(3)^(2-)`
C. `SO_(4)^(2-)`
D. `NO_(3)^(Θ)`

1 Answer

0 votes
by (69.5k points)
selected by
 
Best answer
Correct Answer - A
Bicarbonates on heating form insoluble carbonates.
`MgCl_(2)+2NaHCO_(3)rarr2NaCl+Mg(HCO_(3))_(2)`
`Mg(HCO_(3))_(2)overset(Delta)(rarr)Mg CO_(3)darr.+H_(2)O+CO_(2)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...