Question

The pH of decimolar solution KOH is : 

(a) 1 

(b) 4 

(c) 10 

(d) 13

Answer 1

(d) 13

Concentration of KOH = decimolar or 0.1 M

\(\because\) KOH is strong base, it completely dissociate in solution.

Therefore, \([{\overset{-}{O}{H}}]\) = 0.1 M

\(P^{H}=14+\log\,0.1\)

\(P^{H}=13\)

Answer 2

Option : (d) 13

Answer 3

D. 13

pH of decimolar KOH or potassium hydroxide is extremely high.