Question

Calculate the enthalpy of the reaction,

CH₃COOH_(g) + CH₃CH₂OH_(g) → CH₃COOCH₂CH_3(g) + H₂O_(g)

Bond enthalpies of O-H, C-O, in kJmol^-1 are 464, 351 respectively.

Answer 1

Given,

\(ΔH^0_{O-H}\) = 464 kJ mol^-1;

\(ΔH^0_{C-O}\) = 351 kJ mol^-1.

The given reaction can be represented as,

In this reaction 1O-H and 1C-0 bond of the reactants are broken while 1C-0 and 1O-H bonds of the products are formed.

Enthalpy of reaction,

Hence,

Enthalpy change for the reaction = Δ_rH⁰ = 0.