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Calculate ΔSTotal  and hence show whether the following reaction is spontaneous at 25°C. 

Hg(s) + O2(g) → Hg(I) + SO2(g) ΔH0 = – 238.6 kJ 

ΔS0 = +36.7 JK-1

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Given :

Hg(s) + O2(g) → Hg(I) + SO2(g)

ΔrH0 = – 238.6 kJ

ΔS0 = +36.7 JK-1

T = 273 + 25 = 298 K

ΔSTotal = ?

ΔSTotal = ΔSsys + ΔSsurr

Now,

ΔSsys = 36.7 JK-1

Since the reaction is exothermic, system loses heat to surroundings. 

Hence the entropy of the surroundings increases. 

ΔHsurr = + 238.6 kJ = 238600 J

∵ ΔSTotal > 0, the reaction is spontaneous.

∴ ΔSTotal = 837.4 JK-1

The reaction is spontaneous.

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