Step I. Calculating of no. of moles of `N_(2)`,
`P = 0.987` bar , `V = 0.120 dm^(3)`
`T = (150 + 273) = 423 K` , `R = 0.083 "bar" dm^(3)K^(-1) mol^(-1)`
According to ideal gas equation, `PV = nRT`
`n = (PV)/(RT) = ((0.987 "bar") xx (0.120 dm^(3)))/((0.083 "bar" dm^(3) K^(-1) mol^(-1)) xx (423 K)) = 0.0034` mol
Step II. Calculation of mass of `N_(2)`.
No. of mass of `N_(2) (N) = 0.0034` mol
Molar mass of `N_(2)(M) = 28 gmol^(-1)`
Mass of `N_(2) = n xx M = (0.0034 mol) xx (28 g mol^(-1)) = 0.095 g`
