Question

In the organic compound `CH_(2) = CH – CH_(2) – CH_(2) – C equivCH`, the pair of hydridised orbitals involved in the formation of: `C_(2) – C_(3)` bond is:
`(a) sp – sp_(2) (b) sp – sp_(3) (c) sp_(2 )– sp_(3) (d) sp_(3) – sp_(3)`

Answer 1

`Coverset(6)H_(2) = overset(5)CH –Coverset(4)H_(2) – Coverset(3)H_(2) – overset(2)C equivoverset(1)CH`
In the given organic compound, the carbon atoms numbered as 1, 2, 3, 4, 5, and 6 are sp, sp, `sp^(3), sp^(3), sp^(2)`, and `sp^(2)` hybridized respectively. Thus, the pair of hybridized orbitals involved in the formation of C2-C3 bond is `sp– sp^(3)`.