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The half-life of radium is 16000 yr, after how much time will 1 g radium be reduced to 125 mg?
A. 800 yr
B. 1600 yr
C. 3200 yr
D. 4800 yr

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Correct Answer - d
Given, `t_(1//2) = 1600 yr, N_(0) = 1 g, N = 125 mg = (125)/(1000)g`
We know that, `N = N_(0)((1)/(2))^((t)/(t_(1//2)))`
`(125)/(1000) = ((1)/(2))^(t//1600), (1)/(8) or ((1)/(2))^(3) = ((1)/(2))^(t//1600)`
Hence, `(t)/(1600) = 3 or t = 3xx1600 = 4800 yr`

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