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The electronegativity of `H` and CI are 2.1 and 3.0 respectively. The correct statement `(s)` about the nature of `HCI` is/are:
A. `HCI` is 17% ionic
B. 83% ionic
C. 50% ionic
D. 100% ionic

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Correct Answer - A
% ionic character
`= 16 (X_(A) - X_(B)) +3.5 (X_(A) - X_(B))^(2)`
`=16 (3.0 - 2.1) +3.5 (3.0 - 2.1)^(2)`
`= 17.235`
`= 17%`

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