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जब 0.1 M NaoH तथा `0.01 M HCl` विलयनों के सामान आयतन को मिलाया जाता हैं तो बने विलयन की pH क्या होगी?
A. `2.0`
B. `7.0`
C. `1.04`
D. `12.65`

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Correct Answer - d
`therefore 1` मोल NaOH पूर्णतया उदासीन होता हैं = 1 मोल HCl से `therefore` NaOH के बिना उदासीन हुए बचे मोल `=0.1 -0.01=0.99` मोल
दो विलयनों का सामन आयतन मिलाया अतः
`[OH^(-)]=0.09/2 = 0.045` M
`therefore pOH = -log (0.045) = 1.35`
`therefore pH=14-1.35=12.65`

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