We prepare the cumulative frequency table, as shown below:
Let x and y be the missing frequencies of class intervals 3500 – 4500 respectively.
Then, 25 + x + y = 60
⇒ x + y = 35 ……(1)
Median is 5000, which lies in 4500 – 5500. So, the median class is 4500 – 5500.
∴ l = 4500, h = 1000, N = 60, f = y and cf = 5 + x
Now