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32 g of sulphur will react with 32 g of oxygen, even if more than 32 g of sulphur is available. Which law of chemical combination does it illustrate ?

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32 g of sulphur will react with 32 g of oxygen, even if more than 32 g of sulphur is available. Which law of chemical combination does it illustrate ?
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The illustrates the law of constant composition because sulphur and oxygen are combined in fixed ratio by mass in sulphur dioxide `(SO_(2))` which is formed in this case.
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