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How may millilitres of a `9 N H_(2)SO_(4)` solution will be required to neutralize completely `20mL` of a `3.6 N NaOH` solution ?
A. `18.0mL`
B. `8. 0 Ml`
C. `16.0mL`
D. `80.0 mL`

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Correct Answer - 2
`N_(NaOH)=3.6" "," "V_(NaOH)=20" "," "N_(H_(2)SO_(4))=9" "," "V_(H_(2)SO_(4))=?`
`V_(H_(2)SO_(4))=(3.6xx20)/(9)=8mL`

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