Question

A certain alkaloid has `70.8%` carbon, `6.2%` hydrogen, `4.1%` nitrogen and the rest oxgen. What is its empirical formula :
A. `C_(20)H_(21)NO_(4)`
B. `C_(20)H_(20)NO_(4)`
C. `C_(21)H_(20)NO_(3)`
D. `C_(20)H_(19)NO_(3)`

Answer 1

Correct Answer - A
`"Element % Mole Simplest ratio"`
`C" " 70.8" "70.8//12 = 6 " "6//03 = 20 20`
`H" " 6.2" " 6.2//1 = 6 " " 6//03 = 20 " "20`
`N " "4.1 " "4.1//14 = .3 " "1" " 1 `
`O" "18.9" " 18.9//16 = 1.2" " 4 " "4`
`E.F = C_(20) H_(20) NO_(4)` .