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`60 g` of a compound on analy6sis produced `24 g` C`, `4g`H`, and `32 g O`. The empirical formula of the compound is
A. `CH_(2)O_(2)`
B. `CH_(4)O`
C. `CH_(2)O`
D. `C_(2)H_(4)O_(2)`

1 Answer

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Correct Answer - C
Empirical formula is the simplest type of chemical formula, giving only the proportional of each element present. It can be calculated through the ratio of moles.
`n_(c ) : n_(H) : n_(O) = (24)/(12) : (4)/(1) : (32)/(16) = 2 : 4 : 2 = 1 : 2 : 1`
Thus, the empirical formula is `CH_(2)O`.

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