c) `2 xx 10^(-3)m^(3)`
`therefore` 1L = 1000 `cm^(3)`
and 1m = 100 cm which gives
`(1m)/(100cm)=1=(100cm)/(100cm)`
To get `m^(3)` from the above unit factors, the first unit factor is taken and it is cubed
`(1m)/(100 cm)^(3)`
rArr (1m^(3)/(10^(6)cm^(3))=(1)^(3)=1`
Now, 2L = 2 `xx 1000cm^(3)`
The above is multiplied by unit factor
`2 xx 1000 cm^(3) xx (1m^(3)/(10i^(6)cm^(3))= (2m^(3))/(10^(3))` = 2 xx 10^(-3)m^(3)`
