Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
63 views
in Chemistry by (73.6k points)
closed by
The entropy change involved in the isothermal reversible expansion of 2 moles of an ideal gas from a volume of `10 dm^(3)` to a volume of `100dm^(3)` at `27^(@)C` is
A. `38.3Jmol^(-1)K^(-1)`
B. `35.8Jmol^(-1)K^(-1)`
C. `32.3Jmol^(-1)K^(-1)`
D. `42.3Jmol^(-1)K^(-1)`

1 Answer

0 votes
by (70.6k points)
selected by
 
Best answer
Correct Answer - A
Entropy change for `n` moles of isothenal expansion of an ideal gas from volume `V_(1)` to volume `V_(2)` is
`DeltaS=2.303nR"log"(V_(2))/(V_(1))` ltbr. Hence, `n=2` , `V_(2)=100dm^(3) , V_(1)=10dm^(3)`
`2.303xx2xx8.3143"log"(100)/(10)`
`=38.296Jmol^(-1)K^(-1)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...