Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
87 views
in Chemistry by (73.6k points)
closed by
Weight of one atom an element is `6.44 xx 10^(-23) g`. Calculate g atom of elements in `40 kg`.
A. (a)`10^(3) g` atom
B. (b)`10^(2) g` atom
C. (c )`10^(4) g` atom
D. (d)`10 g` atom

1 Answer

0 votes
by (70.6k points)
selected by
 
Best answer
Correct Answer - a
Weight of Avogadro number `(N)` of atoms of the element
`=6.644xx10^(-23)xx6.023xx10^(23)`
`=40 g`
`40 g`=weight of 1 g atom
`:. 40xx10^(3) g`= weight of `10^(3) g atom`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...