A sample of calcuium carbonate `(CaCO_(3))` has the following percentage composition: `Ca=40%, C=12%, O=48%` If the law of constant proportions is true. Then the weight of calcium in `4 g` of a sample of calcium carbonate obtained from another source will be
A. (a)`0.016 g`
B. (b)`0.10 g`
C. (c )`1.6 g`
D. (d)`16 g`
