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`._(13)Al^(27)` is a stable isotope. `._(13)Al^(29)` is expected to disintegrate by

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`._(13)Al^(27)` is a stable isotope. `._(13)Al^(29)` is expected to disintegrate by
A. `alpha-` emission
B. `beta-` emission
C. postion emission
D. proton emission
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Correct Answer - `(b)`
Nuclides having `(n)/(p) gt 1` undergoes `beta-` emission to decreases `(n)/(p)` in order to attain belt of stablitly i.e.,
`(n)/(p) = 1`
`._(13)^(29)Al rarr ._(14)^(29)Si + ._(-1)e^(0)`
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