Question

6 gm of nitrogen on successive reaction with different compounds gets finally converted into 30 gm `[Cr(NH_(3))_(x)Br_(2)].` Value of x is:
[Atomic mass of Cr=52]

Answer 1

Correct Answer - 4

Answer 2

Applying POAC on N

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The reactions must be along these lines:

N₂ ----^{various treatment}----> [Cr(NH₃)_xBr₂]

2 * Moles of N₂ = x * Moles of [Cr(NH₃)_xBr₂]
2 * 6/28 = x * 30/(212 +17x) [MM of [Cr(NH₃)_xBr₂] = 212 + 17x
x = 4