Calcualte the volume of `Cl_(2)` gas (in ml) liberated at 1 atm 273 K when 1.74 gm `MnO_(2)` reacts with 2.19 gm HCl according to the following with % yeild 40.
`MnO_(2) + 4HCl rightarrow MnCl_(2) + Cl_(2) + 2H_(2)O`
A. 336ml
B. 112ml
C. 134.4ml
D. 44.8ml