Ammonia is produced in accordance with this equation .
`N_(2)(g) + 3H_(2)(g) rightarrow 2NH_(3)(g)`
In a particular experiment, 0.25mol of `NH_(3)` is formed when 0.5 mol of `N_(2)` is reacted with 0.5 mol of `H_(2)`. What is the percent yield?
A. 0.75
B. 0.5
C. 0.33
D. 0.25
