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The elevation in boiling point, when 13.44g of freshly prepared `CuCl_(2)` are added to one kilogram of water, is [Some useful data, `K_(b)(H_(2)O)=0.52"kg K mol"^(-1),"mol.wt. of CuCl"_(2)=134.4gm]`
A. 0.05
B. `0.10`
C. 0.16
D. `0.20`

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Correct Answer - C
`i = 3`, assuming complete ionization of `CuCl_(2)`
`DeltaT=ixxK_(b)xx(w_(B)xx1000)/(m_(B)xxw_(A))`
`=3xx0.52xx(13.44xx1000)/(134.4xx1000)=0.156~~0.16`]

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