# A compound of vanadium has a magnetic moment of 1.73 BM. The electronic configuration of vanadium ion in the compound is:

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A compound of vanadium has a magnetic moment of 1.73 BM. The electronic configuration of vanadium ion in the compound is:
A. [Ar]3d^(2)
B. [Ar]3d^(1)4s^(0)
C. [Ar]3d^(3)
D. [Ar]3d^(0)4s^(1)

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Magnetic moment=sqrt(n(n+1))BM
1.73=sqrt(n(n+2))
sqrt(3)=sqrt(n(n+2))
n=1 (Number of unparied electrons)
V_(22)to3d^(2)4s^(2)
V^(3+)to3d^(1)4s^(0) (has one unpaired electron)