Correct Answer - B
Addition of HBr to 2-pentyne gives two structural isomers (I) and (II).
`CH_(3)-C-=C-CH_(2)CH_(3) overset(HBr) underset((I))(CH_(3)C(Br)=CHCH_(2)CH_(3))+underset((II))(CH_(3)CH=C(Br)CH_(2)CH_(3))`
Each one of these will exist as a pair of geometrical isomers as shown below:
thus, there are two structural and four configurational isomers.