Question

A tyre pumped to a pressure `3.375 atm "at" 27^(@)C` suddenly bursts. What is the final temperature `(gamma = 1.5)`?
A. `27^(@)C`
B. `-27^(@)C`
C. `0^(@)c`
D. `-73^(@)`

Answer 1

`T_(1)^(gamma)P_(1)^(1-gamma)=T_(2)^(gamma)P_(2)^(1-gamma)`
`or ((T_1)/(T_2))^(gamma)=((P_1)/(P_2))^(gamma-1)=((300)/(T_2))^(3//2)=((3.375)/(1))^(3//2-1)`
`T_(2)=(300)/(3.3 75)^(1//3)=200K=-73^(o)C`