Let `T_(1)` and `T_(2)` be the time periods of two springs A and B when a mass m is suspended from them separately. Now both the springs are connected in parallel and same mass m is suspended with them. Now let T be the time period in this position. Then
A. `T = T_(1)+T_(2)`
B. `T=(T_(1)T_(2))/(T_(1)+T_(2))`
C. `T^(2)= T_(1)^(2)+T_(2)^(2)`
D. `1/T^(2)=1/T_(1)^(2)+1/T(2)^(2)`