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Six particles situated at the corners of a regular hexagon of side a move at a constant speed v. Each particle maintains a direction towards the particle at the next corner. Calculate the time the particles will take to meet each other.

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Correct Answer - A::B
A approaches B, B approaches C and so on.
Relative velocity between A and E,
`vecV_(AB)= vecV_A-vecV_B=vecV-vecV cos 60^0`
`=vecV-vecV/2= vecV/2`
` Time, t= (Displacement) /(Velocity) `
`= a/(vecV/2)= (2a)/vecV`.

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