Question

A point starts from rest and moves along a circular path with a constant tangential acceleration. After one rotation, the ratio of its radial acceleration to its tangential acceleration will be equal to
A. 1
B. `2pi`
C. `(1)/(2)pi`
D. `4pi`

Answer 1

Correct Answer - D
`(a_(n))/(a_(t))=(v^(2)//R)/(a)" "("let a"_(t)=a)`
Here, `v^(2)=2al=2a(2piR)=4piR`. Therefore, the ratio is `(4pi)/(1)`.