Correct Answer - A::B::C::D
The specificatiion givenby the compane are,
u=0, m=95m, P_m=3.5hp`
V_m=60km/h`
`=50/3 m/sec`
`t_m=5sec`
So, the maximum acceleration that can be producd is given by,
`=50/(3xx5(=10/3m/sec^2`
So the driving force is given by
`F=ma=95xx(10/3)`
`=950/3N will be`
`v=p/F`
`rarr v=3.5xx746xx3/950`
`=8.2m/sec`
Because teh scooter can reach a maximum of 8.2 m/sec while producing a force of 950/3N. The specification given are some what over claimed.