A single conservative `f_((x))` acts on a `m = 1 kg` particle moving along the x-axis. The potential energy `U_((x))` is given by :
`U_((x)) = 20 + (x - 2)^(2)`
where x is in metres. At `x = 5 m`, a particle has kintetic energy of 20 J
The largest value of x will be:
A. zero
B. `-2`
C. `- sqrt(29) + 2`
D. `sqrt(29) + 2`
