Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
75 views
in Physics by (67.7k points)
closed by
the door of an almirah is 6 ft high, 1.5 ft wide and weights 8 kg. The door is supported by two hinges situated at a distance of 1 ft from the ends. If the magnitude of the forces exerted by the hinges on the door are equal find this magnitude.

1 Answer

0 votes
by (75.2k points)
selected by
 
Best answer
Correct Answer - C::D
According the question
`8g=F_1+F_2`
=N_1=N_2`
Since `R_1=R_2`
Therefore `F_1=F_2`
`rarr 2F_1=8g`
`rarr F_1=40`
Let us take torque about the point B we will get
`N_1xx4=8gx0.75` ltbr `rarr N_1=((50x3))/((4xx4))=15N`
Therefore `sqrt(F_1^2+N_1^2)=R_1`
`=sqrt(40^2+15^2)`
`=42.72=43N`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...